Wiredから最新のニュースを取得し、XMLとしてエクスポート

Wiredから最新のニュースを取得し、APIを使用してXMLとしてエクスポートする方法

入力パラメータ

Parameter Description Type Required Example
source.domain The domain of the news source string Yes wired.com
export The format in which you want to export string No xml
per_page The number of articles to return integer 20 Yes

のためのレシピ cURL

curl --location --globoff --request POST 'https://api.apitube.io/v1/news/everything?source.domain=wired.com&export=xml&per_page=50' \
--header 'Content-Type: application/json'

のためのレシピ Python

import requests

url = "https://api.apitube.io/v1/news/everything"

querystring = {
    "source.domain": "wired.com",
    "export": "xml",
    "per_page": 50
}
response = requests.request("GET", url, params=querystring)

print(response.text)

のためのレシピ Javascript

import axios from "axios"

const options = {
		method: 'GET',
		url: 'https://api.apitube.io/v1/news/everything',
		params: {
    "source.domain": "wired.com",
    "export": "xml",
    "per_page": 50
}};

axios.request(options).then(function (response) {
		console.log(response.data);
}).catch(function (error) {
		console.error(error);
});

のためのレシピ PHP

require 'vendor/autoload.php';

use GuzzleHttp\Client;

$client = new Client();
$response = $client->request('GET', 'https://api.apitube.io/v1/news/everything', [
	'query' => [
    'source.domain' => 'wired.com',
    'export' => 'xml',
    'per_page' => 50,
],
]);

echo $response->getBody();

のためのレシピ Java

OkHttpClient client = new OkHttpClient().newBuilder().build();
MediaType mediaType = MediaType.parse("application/json");
RequestBody body = RequestBody.create(mediaType, "");
Request request = new Request.Builder()
		.url("https://api.apitube.io/v1/news/everything?source.domain=wired.com&export=xml&per_page=50")
		.method("POST", body)
		.addHeader("Content-Type", "application/json")
		.build();
Response response = client.newCall(request).execute();
		
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