获取 Instagram 就绪内容

输入参数

工作流程示例

请求 Instagram 就绪的内容：

curl -X GET "https://api.apitube.io/v1/news/everything?is_instagram_ready=1&category.id=medtop:10000000&api_key=YOUR_API_KEY"

请求 Twitter Card 优化的内容：

curl -X GET "https://api.apitube.io/v1/news/everything?is_twitter_card_ready=1&has_social_share_image=1&api_key=YOUR_API_KEY"

请求 Open Graph 兼容的图片：

curl -X GET "https://api.apitube.io/v1/news/everything?has_social_share_image=1&api_key=YOUR_API_KEY"

相关示例

• 获取具有高质量图像的文章
• 获取大型媒体资讯
• 获取特定图片数量的资讯
• 获取媒体量资讯
• 按参与度分数排序

食谱 cURL

curl --location --globoff --request POST 'https://api.apitube.io/v1/news/everything?is_instagram_ready=1&category.id=medtop%3A10000000&api_key=YOUR_API_KEY&per_page=10' \
--header 'Content-Type: application/json'

食谱 Python

import requests

url = "https://api.apitube.io/v1/news/everything"

querystring = {
    "is_instagram_ready": 1,
    "category.id": "medtop:10000000",
    "api_key": "YOUR_API_KEY",
    "per_page": 10
}
response = requests.request("GET", url, params=querystring)

print(response.text)

食谱 Javascript

import axios from "axios"

const options = {
		method: 'GET',
		url: 'https://api.apitube.io/v1/news/everything',
		params: {
    "is_instagram_ready": 1,
    "category.id": "medtop:10000000",
    "api_key": "YOUR_API_KEY",
    "per_page": 10
}};

axios.request(options).then(function (response) {
		console.log(response.data);
}).catch(function (error) {
		console.error(error);
});

食谱 PHP

require 'vendor/autoload.php';

use GuzzleHttp\Client;

$client = new Client();
$response = $client->request('GET', 'https://api.apitube.io/v1/news/everything', [
	'query' => [
    'is_instagram_ready' => 1,
    'category.id' => 'medtop:10000000',
    'api_key' => 'YOUR_API_KEY',
    'per_page' => 10,
],
]);

echo $response->getBody();

食谱 Java

OkHttpClient client = new OkHttpClient().newBuilder().build();
MediaType mediaType = MediaType.parse("application/json");
RequestBody body = RequestBody.create(mediaType, "");
Request request = new Request.Builder()
		.url("https://api.apitube.io/v1/news/everything?is_instagram_ready=1&category.id=medtop%3A10000000&api_key=YOUR_API_KEY&per_page=10")
		.method("POST", body)
		.addHeader("Content-Type", "application/json")
		.build();
Response response = client.newCall(request).execute();